Assignemnt #86, Letter at a Time

Code

      import java.util.Scanner;
      
      public class LetterAtATime
      {
      	public static void main( String[] args )
      	{
      		Scanner kb = new Scanner(System.in);
      
      		System.out.print("What is your message? ");// if you enter box x is in the second position
      		String message = kb.nextLine();
      
      		System.out.println("\nYour message is " + message.length() + " characters long.");
      		System.out.println("The first character is at position 0 and is '" + message.charAt(0) + "'.");
      		int lastpos = message.length() - 1;
      		System.out.println("The last character is at position " + lastpos + " and is '" + message.charAt(lastpos) + "'.");
      		System.out.println("\nHere are all the characters, one at a time:\n");
      
      		for ( int i=0; i < message.length(); i++ )// if you put that i <= message.length() then you will get an error stating that there are no more letters to see.
      		{
      			System.out.println("\t" + i + " - '" + message.charAt(i) + "'");
      		}
      
      		int a_count = 0;
      
      		for ( int i=0; i < message.length(); i++ )
      		{
      			char letter = message.charAt(i);
      			if ( letter == 'a' || letter == 'A' || letter == 'e' || letter == 'E' || letter == 'i' || letter == 'I' || letter == 'o' || letter == 'O' || letter == 'u' || letter == 'U' )
      			{
      				a_count++;
      			}
      		}
      
      		System.out.println("\nYour message contains " + a_count + " vowels. Isn't that interesting?");
      
      	}
      }

    

Picture of the output